x^2+25x=1625

Solution for x^2+25x=1625 equation:

x^2+25x=1625

We move all terms to the left:

x^2+25x-(1625)=0

a = 1; b = 25; c = -1625;
Δ = b2-4ac
Δ = 252-4·1·(-1625)
Δ = 7125
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{7125}=\sqrt{25*285}=\sqrt{25}*\sqrt{285}=5\sqrt{285}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(25)-5\sqrt{285}}{2*1}=\frac{-25-5\sqrt{285}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(25)+5\sqrt{285}}{2*1}=\frac{-25+5\sqrt{285}}{2}
$